- At t = 0 the switch is closed and the
**capacitor**begins to charge by the battery (explain!). At some later time t [ the charge on the**capacitor****is**q.. In the**circuit**shown, the**capacitor****is****initially****uncharged**.**The**switch S is closed at t = 0. The time instant when**capacitor****is**50% charged is S 2R C w Vo www R BRC 3RC 2 2RC 3 4RC -**In**2 3 2RC In ... **In the circuit**shown, the switch \\'S\\' is closed at `t =0`.**Then capacitor is initially uncharged**. Then the current through the resistor `R = 8Omega` at `t =...**Initially**both switches S1 and S2 are open and**initially**,**capacitor**B has a charge of CE coulomb as shown in the figure and**capacitor**A is**uncharged**. Now switch S1 is closed and S2 remains open till**the capacitor**. a becomes fully charged.- Find the responses of an RLC
**circuit**to a voltage step for different neper frequencies; and 3 Here we have simplified the topology to •**Uncharged capacitors**act like a “short”: V C=Q/C=0 •Fully charged**capacitors**act like an “open**circuit**” Example 1 – Charging**circuit**The selectivity of a**circuit**is dependent upon the amount of.**Capacitors**Solutions.